If 76 is divided into four parts proportional to $7, 5, 3, 4$ , then the smallest part is:

12

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15

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16

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19

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Solution

The correct option is A $12$
Let the parts be $7 x, 5 x, 3 x$ and $4 x .$
$∴ 7 x + 5 x + 3 x + 4 x = 76$
$\Rightarrow 19 x = 76$
$\Rightarrow x = 4$
Hence, the smallest part $= 3 x = 3 \times 4 = 12$

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