If 7A=5B=2C find A:B:C
1.) 35:14:10
2.) 14:10:35
3.) 2:5:7
4.) 10:14:35
Given 7A=5B=2C
⇒7A=5B and 5B=2C
⇒AB=57 .......(i) and BC=25........(ii)
To find A:B:C: We shall make "B" corresponding values equal in above two fractions.
So, multiply equation(i) by 22 and equation(ii) by 77,
we get, AB=57×22 and BC=25×77
AB=1014 and BC=1435
Therefore, A:B=10:14 and B:C=14:35
Hence, A:B:C=10:14:35
Thus, the correct option is (4) (10:14:35)