Question

If $7y^4-25y^2+12=0$, then $y=\pm 3,\pm \frac{2}{\sqrt{7}}$.

• A. Yes
• B. No
• C. Ambiguous
• D. Data insufficient

Answer 1

The correct option is B No

Given equation is:

$7y^4-25y^2+12=0$
$7y^4-21y^2-4y^2+12=0$
$(7y^2-4)(y^2-3)=0$

$\therefore y=\pm \sqrt{3},\pm \frac{2}{\sqrt{7}}$