If 8, 15 and c form a Pythagorean triplet then the value of c is
17
For any natural number m > 1,
we have (2m)2 + (m2 – 1)2 = (m2 + 1)2 .
So, 2m,m2−1 and m2+1 form a Pythagorean triplet.
Here, 2m = 8 or m = 4, then (m2 – 1) = 16 - 1 = 15.
Therefore, c = (m2+1) = 16 + 1 = 17.