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Question

If 8, 2 are the roots of x2+ax+β=0 and 3, 3 are the roots of x2+αx+b=0 , then the roots of x2+ax+b=0 are


A

9, 1

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B

– 9, 2

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C

-8, -2

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D

8, - 1

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Solution

The correct option is A

9, 1


8, 2 are the roots of x2+ax+β=0

8+2=10= a,8.2=16=β i.e.,a= 10,β=16

3, 3 are the roots of x2+αx+b=0

3+3=6=α,3.3=bi.e,α= 6,b=9

Now, x2+ax+b=0 becomes
x210x+9=0

or (x 1)(x 9)=0x=1,9


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