Question

If 8.3 mL of a sample of $H_2{SO}_4$ (36 N) is diluted by 991.7 mL of water, the approximate normality of the resulting solution is:

• A. 0.4
• B. 0.2
• C. 0.1
• D. 0.3

Answer 1

The correct option is D 0.3

$V_1{N}_1$ = $V_2{N}_2$

$V_2$ = 8.3 + 991.7

Substituting the values,

$8.3\times 36=1000\times N_2$

$N_2=8.3\left(\frac{36}{1000}\right)$

= 0.2988 N