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Question

If 883+683 is divided by 49, then the remainder is

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Solution

883+683=(1+7)83(17)83=2[ 83C17+ 83C373++ 83C83783]=2× 83C17+49k, kZ=(2×83×7)+49k=166×7+49k=161×7+49k+5×7=49(k+23)+35

Therefore, the remainder is 35.

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