If 8 is subtracted from twice the cube of 5, then the result is not divisible by
Give expressions in the following cases.
(a) 11 added to 2m
(b) 11 subtracted from 2m
(c) 5 times y to which 3 is added
(d) 5 times y from which 3 is subtracted
(e) y is multiplied by − 8
(f) y is multiplied by − 8 and then 5 is added to the result
(g) y is multiplied by 5 and the result is subtracted from 16
(h) y is multiplied by − 5 and the result is added to 16
What must be subtracted from 3x3−8x2+4x−3 so that the resulting expression is divisible by x−2?