If 800 - 8- 108 - x-3-2- then x -

The correct option is C 10^4 800=8× 10^8× x^ 3/2 ⇒ #160; 8008× 10^8=x^ 3/2 ⇒ #160; 10010^8=1√(x^3) ⇒ #160; 110 ...

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Standard VIII

Mathematics

Adding Consecutive Odd Numbers

If 800 = 8×...

Question

If $800 = 8 \times 10^{8} \times x^{- 3 / 2}$ , then $x =$

10^{2}

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10^{3}

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10^{4}

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10^{5}

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Solution

The correct option is C $10^{4}$
$800 = 8 \times 10^{8} \times x^{- 3 / 2}$

$\Rightarrow$ $\frac{800}{8 \times 10^{8}} = x^{- 3 / 2}$

$\Rightarrow$ $\frac{100}{10^{8}} = \frac{1}{\sqrt{x^{3}}}$

$\Rightarrow$ $\frac{1}{10^{6}} = \frac{1}{\sqrt{x^{3}}}$

$\Rightarrow$ $\frac{1}{10^{12}} = \frac{1}{x^{3}}$ [Taking square on both sides]

$\Rightarrow$ $\frac{1}{10^{4}} = \frac{1}{x}$ [Taking cube root on both sides]

$∴$ $x = 10^{4}$

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Similar questions

Write the numeral whose expanded form is given below:
(i) $6 \times 10^{4} + 3 \times 10^{3} + 0 \times 10^{2} + 7 \times 10^{1} + 8 \times 10^{0}$
(ii) $9 \times 10^{6} + 7 \times 10^{5} + 0 \times 10^{4} + 3 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 2 \times 10^{0}$
(iii) $8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 2 \times 10^{2} + 9 \times 10^{1} + 6 \times 10^{0}$

Find the number from each of the following expanded forms:

(a) 8 × 10⁴ + 6 × 10³ + 0 × 10² + 4 × 10¹ + 5 × 10⁰

(b) 4 × 10⁵+ 5 × 10³+ 3 × 10²+ 2 × 10⁰

(d) 9 × 10⁵ + 2 × 10² + 3 × 10¹

Question 61

$876543 = 8 \times 10^{5} + 7 \times 10^{4} + 6 \times 10^{3} + 5 \times 10^{2} + 4 \times 10^{1} + 3 \times 10^{0}$

Q. Express the number :

8 \times 10^{5} + 7 \times 10^{4} + 5 \times 10^{3} + 4 \times 10^{2} + 6 \times 10^{1} + 9 \times 10^{0}

Q. Write the number :

4 \times 10^{6} + 8 \times 10^{5} + 6 \times 10^{4} + 4 \times 10^{3} + 4 \times 10^{2} + 6 \times 10 + 9 \times 10^{0}

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If 800=8×108×x−3/2, then x=

The correct option is C 104800=8×108×x−3/2⇒ 8008×108=x−3/2⇒ 100108=1√x3⇒ 1106=1√x3⇒ 11012=1x3 [Taking square on both sides]⇒ 1104=1x [Taking cube root on both sides]∴ x=104

If $800 = 8 \times 10^{8} \times x^{- 3 / 2}$ , then $x =$