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Question

If 81 is discriminant of 2x2+5x−k=0 then the value of k is

A
5
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B
7
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C
7
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D
2
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Solution

The correct option is A 7
the given equation 2x2+5xk=0 is in the form of ax2+bx+c

By comparing a=2,b=5,c=k

Given, Descriminant D=81 (D=b24ac)

By equating,
b24ac=81

25+8k=81

8k=8125

8k=56

k=7

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