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Question

If 8iz3+12iz2−18z+27i=0, then the value of |z| is

A
3/2
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B
2/3
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C
1
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D
3/4
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Solution

The correct option is A 3/2
8iz3+12iz218z+27i=0

=4iz2(2z3i)9(2z3i)=0

=(2z3i)(4iz29)=0

=z=3i2 & z2=94i

|z|=32 & |z|2=94

Hence |z|=32

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