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(x±a)(x±b) = x²±(a+b)x+ab.

If 8 x+1=64, ...

Question

If $8^{x + 1}$ = 64 , what is the value of $3^{2 x + 1}$ ?

(a) 1
(b) 3
(c) 9
(d) 27

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Solution

We have to find the value of provided

So,

Equating the exponents we get

By substitute in we get

The real value of is

Hence the correct choice is .

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If $8^{x + 1}$ = 64, what is the value of $3^{2 x + 1}$ ?

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(x±a)(x±b) = x²±(a+b)x+ab.

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