wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If 9.2x+0.8x99xx+11, then:

A
x110
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
x110
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
x10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
x10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A x110
Given: 9.2x+0.8x99xx+11

Simplify the inequality to it's full extent.
10x100x+11 [9.2x+0.8x=10x,99xx=100x]

Add 100x on both sides:
10x+100x100x+100x+11 [10x+100x=110x and100x+100x=0]
110x11

Shift 110 to the denominator of R.H.S
x11110
x110

A closed circle at 110 and the red line goes to the left, indicating that x is less than or equal to 110

Hence, (a.) is the correct choice.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Solving Inequalities Involving Decimals
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon