Question

If $9>3v-3$, find the greatest possible integer value of $v$.

• A. $3$
• B. $2$
• C. $4$
• D. $6$

Answer 1

Answer: (A)

$3$

Gven that $9>3v-3$

Add $3$ both the sides, we get

$9+3>3v-3+3$

$\Rightarrow 12>3v$

Divided both side by $3$, we get

$\frac{12}{3}>\frac{3v}{3}$

$\Rightarrow 4>v$

So $v<4$

Then $v$ is $3$.