Question

If 9.8 gms of $H_{2}S{O}_4$ is neutralised exactly with a strong alkali, the heat evolved is: ($\Delta H$ of neutralisation is 13.6 kcal)

• A. 13.6 kcal
• B. 1.36 kcal
• C. 2.72 kcal
• D. 27.2 kcal

Answer 1

The correct option is C 2.72 kcal

$H_{2}S{O}_4\to 2H^{+}+S{O}_4^{2-}$
9.8 gms $=\frac{9.8}{98}=0.1$ mole of $H_{2}S{O}_4$ $=$ 0.2 mole of $H^{+}$ ion in aqueous medium
$\Delta H$ of neutralization is 13.6 kcal.

The heat evolved $=0.2\times 13.6=2.72kcal$

Option C is correct.