Question

If 9 + (81)^x = 1/27^x-3 , find x

Answer 1

9×81^x = 1/27^x-3

3²×3^4x = (1/3)^3(x-3)

3^2+4x = 3^-[3(x-3)]

Bases are equal. Exponents must be equal.

2+4x = -(3x-9)

2+4x = -3x+9

4x+3x = 9-2

7x = 7

x = 7/7

x = 1

Therefore, the value of x is 1