If 9:a::a:16, then a=
Two ratios are in proportion then product of their extreme terms is equal to the product of their middle terms.
If a:b::c:d
then, a×d=b×c
Here, 9:a::a:16
Then, 9×16=a×a
⇒ a×a=9×16
⇒a2=144
⇒a=144
⇒a=12×12
⇒a=12
Hence, the value of ais12
(−34)2=?
(a)−916
(b)916
(c)169
(d)−169
If |x+2|≤9,then
Choose an appropriate answer and fill in the blanks:
9 less than a number is 16……..
[9-x=16/x-9=16]