Question

If $9\sqrt{x}=\sqrt{12}+\sqrt{147}$ ,then the value of $x$ is

• A. $-2$
• B. $2$
• C. $3$
• D. $-3$

Answer 1

The correct option is C

$3$

Find the value of $x$:

Given,

$9\sqrt{x}=\sqrt{12}+\sqrt{147}$

$\Rightarrow$$9\sqrt{x}=2\sqrt{3}+7\sqrt{3}$

$\Rightarrow$$9\sqrt{x}=9\sqrt{3}$

$\mathbf{\therefore }\mathit{x}\mathbf{}\mathbf{=}\mathbf{}\mathbf{3}$

Hence, Option ‘C’ is correct