If $9, x, x$ and $49$ are in proportion, find the value of $x$ .

$21$

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$35$

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$14$

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$7$

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Solution

The correct option is A
$21$

Given: $9, x, x, 49$ are in proportion i.e. $9 : x :: x : 49$
$\Rightarrow \frac{9}{x} = \frac{x}{49}$

$\Rightarrow x \times x = 9 \times 49$
$\Rightarrow x \times x = 441$
$\Rightarrow x \times x = 21 \times 21$
$\Rightarrow x = 21$

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$I f 3 x - 7 y = 10 a n d x y = - 1, f i n d t h e v a l u e o f 9 x^{2} + 49 y^{2}$

If 9, x, x and 49 are in proportion, find the value of x.

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