If 92U235 assumed to decay only by emitting two - - and one - - participle- the possible product of decay is -

The correct option is B _89Ac^227 _92U^235→ _ZX^A + 2_2He^4 + _ 1e^0 Equating the mass number of both sides235 = A + 2 × 4 + 0 ∴ A = 235 ...

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Byju's Answer

Standard VII

Chemistry

Sub-Atomic Particles

If 92U235 a...

Question

If $_{92} U^{235}$ assumed to decay only by emitting two $α$ - and one $β$ - participle, the possible product of decay is :

_{89} A c^{231}

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_{89} A c^{235}

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_{89} A c^{236}

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_{89} A c^{227}

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Solution

The correct option is B $_{89} A c^{227}$
$_{92} U^{235} \to_{Z} X^{A} + 2_{2} H e^{4} +_{- 1} e^{0}$
Equating the mass number of both sides
235 = A + 2 $\times$ 4 + 0
$∴$ A = 235 - 8 = 227
Similarly, equating ato,ic number of both sides
92 = Z + 2 $\times$ 2 - 1
$∴$ Z = 92 - 3 = 89
$∴_{Z} X^{A} =_{89} A c^{227}$

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If 92U235 assumed to decay only by emitting two α - and one β - participle, the possible product of decay is :

The correct option is B 89Ac22792U235→ZXA+22He4+−1e0Equating the mass number of both sides235 = A + 2 × 4 + 0∴ A = 235 - 8 = 227Similarly, equating ato,ic number of both sides92 = Z + 2 × 2 - 1∴ Z = 92 - 3 = 89∴ZXA=89Ac227

If $_{92} U^{235}$ assumed to decay only by emitting two $α$ - and one $β$ - participle, the possible product of decay is :