if 995² = (ab) 100+c, where a,b and c are natural numbers, then what is the value of
a-bc?

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Solution

Dear Student,

$995^{2} = 990025 c o n v e r t i n g i t i n f o r m o f (a \times b) \times 100 + c 990025 = 990000 + 25 = (100 \times 99) \times 100 + 25 h e n c e a = 100, b = 99 a n d c = 25 o r a = 9, b = 100 a n d c = 25 v a l u e o f a - b c = 100 - 99 \times 25 o r 99 - 100 \times 5 = 100 - 2475 o r 99 - 2500 = - 2375 o r - 2401$
Regards,

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