Question

If $9999=4$, $8888=8$, $1816=6$, $1212=0$, then, $1919=$?

Answer 1

Find the value of the required number following the pattern

The holes in a number count as one point each.

Then you multiply The number of unique numbers that have holes in them by the number of holes.

$9999=4$

Each $9$ has one hole, so they are a total of $4$ points

There is only one unique number $9$ that scores points, so we multiply $1\left(4\right)=4$

$8888=8$

Each $8$ has two holes, so each $8$ counts as two points, so we find their sum $2+2+2+2=8$

There is only one unique number $8$ that scores points, so we multiply $1\left(8\right)=8$

$1816=6$

The $8$ has two holes ($2$ points) and the $6$ has one hole ($1$ point). Add those together $(2+1=3)$. There are two unique numbers that score points, so multiply the sum by $(2+1)\times 2=6$

$1212=0$

Since, none of the numbers have holes in them.

Following the same rule,$1919$ has two holes(one hole in each $9$) and there is one unique number, so $2\times 1=2$.

Hence, $1919=2$.