Question

If $a=0.1039$, then the value of $\sqrt{4a^2-4a+1}+3a$ is:

• A. $0.1039$
• B. $0.2078$
• C. $1.1039$
• D. $2.1039$

Answer 1

The correct option is C $1.1039$

$\sqrt{4a^2-4a+1}+3a$

$=\sqrt{1^2+(2a{)}^2-2\times 1\times 2a}+3a$

$=\sqrt{(1-2a{)}^2}+3a$

$=1-2a+3a$

$=1+a$

$=1.1039$