If a - 0-1039- then what is the value of 3a-4a2 - 4a - 1-

We have to find the value of: 3a √(4a^2 4a + 1) Now, 4a^2 2a 2a + 1 =2a (2a 1) (2a 1) =(2a 1)(2a 1) = (2a 1)^2 3a √((2a 1)^2) = 3a 2a + 1 = a+ ...

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Algebraic Identities

If a = 0.1039...

Question

If a = 0.1039, then what is the value of $3 a - \sqrt{4 a^{2} - 4 a + 1}$ ?

0.1039

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0.2078

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1.1039

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2.1039

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Solution

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a = 0.1039

\sqrt{4 a^{2} - 4 a + 1} + 3 a

3 a - \sqrt{4 a^{2} - 4 a + 1}

3 a - \sqrt{4 a^{2} - 4 a + 1}

\sqrt{4 a^{2} - 4 a + 1} + 3 a

a^{2} - 4 a - 1 = 0, a \neq 0

a^{2} + 3 a + \frac{1}{a^{2}} - \frac{3}{a}

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