If a = 0.1039, then what is the value of 3a−√4a2−4a+1?
A
0.1039
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B
0.2078
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C
1.1039
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D
2.1039
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Solution
The correct option is C
1.1039
We have to find the value of:- 3a−√4a2−4a+1 Now, 4a2−2a−2a+1 =2a(2a−1)−(2a−1) =(2a−1)(2a−1)=(2a−1)2 ∴3a−√4a2−4a+1=3a−√(2a−1)2=3a−2a+1=a+1 =0.1039+1=1.1039