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Question

If a0,a1,a2....be the coefficients in the expansion of (1+x+x2)n in ascending powers f(x) , then prove that :
ar=a2nr

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Solution

(1+x+x2)n=a0+a1x+a2x2++a2nx2n=2nr=0arxr
Replace x by 1x.
(1+1x+1x2)2=a0+a1(1x)+a2(1x2)+
or (1+x+x2)nx2n=a0+a1(1x)++ar(1xr)+
or (1+x+x2)n=a0x2n+a1x2n1++arx2nr+
2nr=0arxr=2nr=0a2n+rr, by (1)(2)
Equating the coefficients of x2nr in both sides, we get a2nr=arorar=a2nr, where 0 < r < 2n

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