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B
√∣a∣bi
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C
√∣a∣b
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D
None of these
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Solution
The correct option is C√∣a∣bi √a.√b =√ab However a<0 and b>0 Hence −a>0. Thus √ab is imaginary. Hence √ab =√−|a|b since a<0 but |a|>0 =√i2|a|b =i√|a|.b