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Question

If a < 0 < b , then ba|x|xdx=

A
ba
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B
ab
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C
a+b
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D
0
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Solution

The correct option is C a+b
Now,
ba|x|xdx; [ a<0<b]

=0a|x|xdx+b0|x|xdx

=0axxdx+b0xxdx

=0a(1)dx+b0(1)dx

=(0a)+(b0)

=b+a.

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