You visited us 2 times! Enjoying our articles? Unlock Full Access!

Zeroes of a Polynomial

if A=0, B =X:...

Question

if A=(0), B =(X:X>15 and x<5), c=(x:x-5=0), D=(x: $x^{2}$ =25) E=(x :xis a positive integer root of equation $x^{2}$ -2x-15 =0, then pair of equal sets is:

A, B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B, C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C, D

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C, E

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $A, B$
$A = {0}$

$B = {0}$ as no such element s.t $x > 15$ and $x < 5$

$C = {5}$ $x : x - 5 = 0$

$D = {- 5, 5}$ $x^{2} - 25 ⟹ x = - 5, 5$

$E = {- 3, 5}$

Roots of the equation $x^{2} - 2 x - 15 = 0$

$⟹ (x - 5) (x + 3) = 0$

$⟹ x = - 3, 5$

So the pair of equal sets are $A$ and $B$ .

Suggest Corrections

Similar questions

Q. Find the pairs of equal sets, if any, give reasons:

A = {0}, B = {x : x > 15 and x < 5}

C = {x : x - 5 = 0}, D = {x : x^{2} = 25}

E = {x : x

is an integral positive root of the equation of

x^{2} - 2 x - 15 = 0}

Q. Write the set builder form

A = {- 1, 1}

Let a and b be nonzero real roots of the quadratic equation x²+ ax + b = 0 and a + b, a -b and - a -b be the roots of the equation x⁴+ax³+cx²+dx+e=0. Then which of the following statement is false?

Q. State which of the following sets are disjoint
(i)

A = {2, 4, 6, 8}; B =

{

x : x

is an even number

< 10, x \in N}

(ii)

X = {1, 3, 5, 7, 9}, Y = {0, 2, 4, 6, 8, 10}

(iii)

P =

{

x : x

is a prime

< 15

}

Q =

{

x : x

is a multiple of 2 and

x < 16

}

(iv)

R = {a, b, c, d, e}, S = {d, e, a, b, c}

Which of the following pairs of sets are disjoint?

(i) {1, 2, 3, 4} and {x : x is a natural number and 4 $\leq x \leq 6$ }

(ii) {a, e, i, o, u} and {b, c, d, f}

(iii) {x : x is an even integer} and {x : x is an odd integer}

Join BYJU'S Learning Program

if A=(0), B =(X:X>15 and x<5), c=(x:x-5=0), D=(x:x2=25) E=(x :xis a positive integer root of equation x2-2x-15 =0, then pair of equal sets is:

The correct option is A A,BA={0}B={0} as no such element s.t x>15 and x<5C={5} x:x−5=0D={−5,5} x2−25⟹x=−5,5E={−3,5} Roots of the equation x2−2x−15=0⟹(x−5)(x+3)=0⟹x=−3,5So the pair of equal sets are A and B.

if A=(0), B =(X:X>15 and x<5), c=(x:x-5=0), D=(x: $x^{2}$ =25) E=(x :xis a positive integer root of equation $x^{2}$ -2x-15 =0, then pair of equal sets is: