MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Mathematical Statements

If a < 0, t...

Question

If $a < 0$ , then function $f (x) = a x^{2} + b x + c$ has

A

minimum value.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

constant value.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

maximum value.

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

D

positive value.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D maximum value.
When $a < 0$ , $f (x)$ has maximum value because as we increase the value of $x$ the value of $f (x)$ keeps on decreasing as shown

Suggest Corrections

thumbs-up

0

Similar questions

a < 0

, then the function

f (x) = a x^{2} + b x + c

k \in R

lies between the roots of

a x^{2} + b x + c = 0, a < 0

f (x) = a x^{2} + b x + c = 0

f (k)

&

ϵ

R such that a + b + c = 0 and a + b - c = 0, then the polynomial function

f (x) = a x^{2} + b x + c

(a > 0)

attains its least value at 'x' equal to

f (x) = a x^{2} + b x + c

has no real zeroes and

a + b + c < 0

f (x) = a x^{2} + b x + c

has no real zeros and

a + b + c < 0

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Mathematical Statements

MATHEMATICS

Watch in App

explore_more_icon

Explore more

Mathematical Statements

Standard IX Mathematics

Join BYJU'S Learning Program

CrossIcon