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Question

If A={0,1,2,3,5},B={0,1,2,3},C={0,1,4,5}, then n(AΔB)+n(BΔC)+n(CΔA) is equal to

A
10
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B
7
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C
8
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D
9
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Solution

The correct option is C 8
AB={5},BA={ }
AΔB={5}

BC={2,3},CB={4,5}
BΔC={2,3,4,5}

CA={4},AC={2,3}
CΔA={2,3,4}

n(AΔB)++n(BΔC)+n(CΔA)
=1+4+3=8

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