If A(-1, 0), B(5, -2) and C(8, 2) are the vertices of a $△ A B C$ then its centroid is

(a) (12, 0) (b) (6, 0) (c) (0, 6) (d) (4, 0)

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Solution

As we know the coordinates of the centroid (x,y)of the triangle is $x equals fraction numerator x subscript 1 plus x subscript 2 plus x subscript 3 over denominator 3 end fraction y equals fraction numerator y subscript 1 plus y subscript 2 plus y subscript 3 over denominator 3 end fraction$

$x equals fraction numerator negative 1 plus 5 plus 8 over denominator 3 end fraction equals 12 over 3 equals 4$
$y equals fraction numerator 0 plus left parenthesis negative 2 right parenthesis plus 2 over denominator 3 end fraction equals 0 h e n c e space t h e space c e n t r o i d space i s space left parenthesis 4 comma 0 right parenthesis$

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Similar questions

△ A B C

B (- 3, 1)

C (0, - 2)

(- 4, 0)

(1, - 1)

4 sq.units

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