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Question

If A = {-1, 1}, Find A×A×A

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Solution

A={1,1}

A×A={(1,1),(1,1),(1,1),(1,1)}

A×(A×A)={1,1}×{(1,1),(1,1),(1,1),(1,1)}={(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1),(1,1,1)}


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