If a1=1 and an+1−3an+2=4n for every positive integer n, then a100 equals
Option (c)
Write options as
a) 3n−1−2n,
b) 3n−1+2n,
c) 3n−2n,
d) 3n+2n,
e) 3n−1−n
Check for n = 1, an=1
For a positive integer n, let a(n)=1+12+13+14…+12n−1 then