The correct option is
A {(1,3),(2,3),(3,3),(1,4),(2,4),(3,4),(3,1),(4,1),(3,2),(4,2),(4,3)}(A×B)={(1,3),(1,4),(2,3),(2,4),(3,3),(3,4)}
(B×A)={(3,1),(3,2),(3,3),(4,1),(4,2),(4,3)}
⇒(A×B)∪(B×A)={(1,3),(1,4),(2,3),(2,4),(3,3),(3,4),(3,1),(3,2),(4,1),(4,2),(4,3)}