If A = {1, 3, 5, 7, 9, 11, 13, 15, 17}, B ={2, 4, ......, 18} and N, the set of natural numbers is the universal set, then (A′∪[(A∪B)∩B′]) is
A
ϕ
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B
N
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C
A
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D
B
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Solution
The correct option is B N Using distributive property of sets (intersection over union), we have A′∪[(A∪B)∩B′]=A′∪[(A∩B′)∪(B∩B′)]=A′∪[(A∩B′)∪ϕ]=A′∪(A∩B′)=(A′∪A)∩(A′∪B′)=N∩(A∩B)′=(A∩B)′=ϕ′=N.