If A -1-8-27 and B - x - x - n 3- n - N - n -4- then A and B are sets -A- equalB- disjointC- infiniteD- singleton

The correct option is A equal Given, A = {1, 8, 27} B={x : x = n^3, n ∈ N, n lt; 4}. The values of n are 1, 2 and 3. Thus, the elements of B are 1^3, 2^3 ...

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Standard IX

Mathematics

Equal and Equivalent Sets

If A =1,8,27 ...

Question

If $A = {1, 8, 27}$ and $B = {x : x = n^{3}, n \in N, n < 4},$ then A and B are ___ sets.

equal

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disjoint

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infinite

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singleton

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Solution

The correct option is A
equal

Given,

$A = {1, 8, 27} B = {x : x = n^{3}, n \in N, n < 4} .$

The values of $n$ are 1, 2 and 3.
Thus, the elements of B are $1^{3}, 2^{3}$ and $3^{3} .$
$∴ B = {1, 8, 27}$

As the sets A and B have the same elements, they are equal sets.

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If A={1,8,27} and B={x:x=n3,n∈N,n<4},then A and B are ___ sets.

The correct option is A equal Given, A={1,8,27}B={x:x=n3,n∈N,n<4}. The values of n are 1, 2 and 3. Thus, the elements of B are 13,23 and 33. ∴B={1,8,27} As the sets A and B have the same elements, they are equal sets.

If $A = {1, 8, 27}$ and $B = {x : x = n^{3}, n \in N, n < 4},$ then A and B are ___ sets.

The correct option is A
equal

Given,

$A = {1, 8, 27} B = {x : x = n^{3}, n \in N, n < 4} .$

The values of $n$ are 1, 2 and 3.
Thus, the elements of B are $1^{3}, 2^{3}$ and $3^{3} .$
$∴ B = {1, 8, 27}$

As the sets A and B have the same elements, they are equal sets.