If A (-1, 8), B(4, -2) and C(-5, -3) are the vertices of a triangle. Median through(-1, 8) intersect line segment BC at D. Find the co-ordinates of point D.

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Solution

The correct option is C

Since, AD is the median of the triangle ABC.

So, D should be the midpoints of side BC

Co-ordinates of points D(x,y)

D(x,y) = $(\frac{4 - 5}{2}, \frac{- 2 - 3}{2}) = (\frac{- 1}{2}, \frac{- 5}{2})$

Co-ordinates of point D = $(\frac{- 1}{2}, \frac{- 5}{2})$

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If A (-1, 8), B(4, -2) and C(-5, -3) are the vertices of a triangle. Median through(-1, 8) intersect line segment BC at D. Find the co-ordinates of point D.

The correct option is C Since, AD is the median of the triangle ABC. So, D should be the midpoints of side BC Co-ordinates of points D(x,y) D(x,y) = (4−52,−2−32)=(−12,−52) Co-ordinates of point D = (−12,−52)

The correct option is C

Since, AD is the median of the triangle ABC.

So, D should be the midpoints of side BC

Co-ordinates of points D(x,y)

D(x,y) = $(\frac{4 - 5}{2}, \frac{- 2 - 3}{2}) = (\frac{- 1}{2}, \frac{- 5}{2})$

Co-ordinates of point D = $(\frac{- 1}{2}, \frac{- 5}{2})$