If A1,A2,...,A100 are sets such that n(Ai)=i+2,A1⊂A2⊂A3........A100 and ⋂100i=3Ai=A, then n(A)=
A
3
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B
4
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C
5
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D
6
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Solution
The correct option is B5 We have n(Ai)=i+2 ∴n(A1)=3,n(A2)=4,n(A3)=5 Similarly n(A100)=102 given A1⊂A2⊂A3........⊂A100 As A3 is a subset of all the successive sets ∴A3∩A4∩A5∩........∩A100=A3 ∴A3=A ∴n(A)=n(A3)=5