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Question

If a1,a2,a3(a1>0) are in G. P. with common ratio r, then the value of r, for which the inequality 9a1+5a3>14a2 holds, can not lie in the interval

A
[1,)
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B
[1,9/5]
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C
[4/5,1]
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D
[5/9,1]
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Solution

The correct option is A [1,9/5]
a1,a2,a3G.P
common ration = r
a2=a1ra3=a1r29a1+5a3>14a29a114a1r+9>05r29r5r+9>0r(5r9)1(5r9)>0(r1)(5r9)>0(r1)(r95)>0r(,1)(95,)r[1,95]

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