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General Term of an AP

If a1, a2, a3...

Question

If $a_{1}, a_{2}, a_{3}, a_{4}$ are terms of an AP, then the relation between them is

A

a_{1} + a_{2} = a_{2} + a_{3}

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B

a_{1} + a_{4} = a_{2} + a_{3}

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C

a_{1} + a_{3} = a_{2} + a_{4}

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Solution

The correct option is B $a_{1} + a_{4} = a_{2} + a_{3}$
The sum of the first term and the last term is equal to the sum of the second term and the second last term and so on.
Hence, $a_{1} + a_{4} = a_{2} + a_{3}$

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Similar questions

a_{1}, a_{2}, a_{3}, a_{4}

are terms of an AP, then the relation between them is

a_{1}, a_{2}, a_{3}

a_{4}

a_{1} + a_{4} = 10

a_{2} \cdot a_{3} = 24

, then the least term of them is

a_{1}, a_{2}, a_{3}, a_{4}

are in AP, then

\frac{1}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{1}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \frac{1}{\sqrt{a_{3}} + \sqrt{a_{4}}}

a_{1}, a_{2}, a_{3}, a_{4}, . . {. ., a}_{20}

a_{1} + a_{20} = 45

a_{1} + a_{2} + a_{3} + a_{4}, . . {. . + a}_{20}

a_{1}, a_{2}, a_{3}, . . . . . . . a_{n}

are first n terms of an A.P. with first term

a_{1} = 0

and common difference

d \neq 0

\frac{a_{3} - a_{2}}{a_{2}} + \frac{a_{4} - a_{2}}{a_{3}} + \frac{a_{5} - a_{2}}{a_{4}} . . . . . . . . . . . . \frac{a_{n} - a_{2}}{a_{n - 1}}

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