If $a_{1}, a_{2}, a_{3}, a_{4}$ are terms of an AP, then the relation between them is

a_{1} + a_{2} = a_{2} + a_{3}

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a_{1} + a_{4} = a_{2} + a_{3}

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a_{1} + a_{3} = a_{2} + a_{4}

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Solution

The correct option is B $a_{1} + a_{4} = a_{2} + a_{3}$
The sum of the first term and the last term is equal to the sum of the second term and the second last term and so on.
Hence, $a_{1} + a_{4} = a_{2} + a_{3}$

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Similar questions

a_{1}, a_{2}, a_{3}, a_{4}

If $a_{1}, a_{2}, a_{3}, a_{4}$ are in AP, then

a_{1}, a_{2}, a_{3}, a_{4}, a_{5} > 0

\frac{a_{1}}{a_{2} + a_{3}} + \frac{a_{2}}{a_{3} + a_{4}} + \frac{a_{3}}{a_{4} + a_{5}} + \frac{a_{4}}{a_{5} + a_{1}} + \frac{a_{5}}{a_{1} + a_{2}} \geq \frac{5}{2}

a_{1}, a_{2}, a_{3}, a_{4}

\frac{1}{\sqrt{a_{1}} + \sqrt{a_{2}}} + \frac{1}{\sqrt{a_{2}} + \sqrt{a_{3}}} + \frac{1}{\sqrt{a_{3}} + \sqrt{a_{4}}}

a_{1}, a_{2}, a_{3}

a_{4}

a_{1} + a_{4} = 10

a_{2} \cdot a_{3} = 24

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