If a 1- a 2- a 3- a 4 are the coefficients of any four consecutive terms in the expansion of 1-xn- then a 1- a 1- a 2- a 3- a 3- a 4-A- a2-a2-a3B- 1-2a2-a2-a3C- 2 a2-a2-a3D- 2 a3-a2-a3

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Byju's Answer

Standard XI

Mathematics

General Term of Binomial Expansion

If a 1, a 2, ...

Question

If $a_{1}, a_{2}, a_{3}, a_{4}$ are the coefficients of any four

consecutive terms in the expansion of ( $1 + x)^{n}$ , then

$\frac{a_{1}}{a_{1} + a_{2}}$ + $\frac{a_{3}}{a_{3} + a_{4}}$ =

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Solution

The correct option is C

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Similar questions

a_{1}, a_{2}, a_{3}, a_{4}

are coefficients of any 4 consecutive terms in the expansion of (

1 + x)^{n}

, then

\frac{a_{1}}{a_{1} + a_{2}} + \frac{a_{3}}{a_{3} + a_{4}} =

If $a_{1}, a_{2}, a_{3}$ and $a_{4}$ are the coefficients of four consecutive terms in the expansion of $(1 + x)^{n},$ prove that $\frac{a_{1}}{a_{1} + a_{2}} + \frac{a_{3}}{a_{3} + a_{4}} = \frac{2 a_{2}}{a_{2} + a_{3}} .$

If $a_{1}, a_{2}, a_{3}, a_{4}$ be the coefficeints of four consecutive terms in the expansion of $(1 + x)^{n}$ then prove that
$\frac{a_{1}}{a_{1} + a_{2}} + \frac{a_{3}}{(a_{3} + a_{4})} = \frac{2 a_{2}}{(a_{2} + a_{3})} .$

If $a_{1}, a_{2}, a_{3}, a_{4}$ are the coefficients of any four consecutive terms in the expansion of $(1 + x)^{n}$ , then $\frac{a_{1}}{a_{1} + a_{2}} + \frac{a_{3}}{a_{3} + a_{4}} =$

Q. If the coefficient of

4

consecutive terms in the expansion of

(1 + x)^{n}

are

a_{1}, a_{2}, a_{3}, a_{4}

respectively , then show that:

\frac{a_{1}}{a_{1} + a_{2}} + \frac{a_{3}}{a_{3} + a_{4}} = \frac{2 a_{3}}{a_{2} + a_{3}}

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If a1,a2,a3,a4 are the coefficients of any four consecutive terms in the expansion of (1+x)n, then a1a1+a2 + a3a3+a4 =

The correct option is C verify options

If $a_{1}, a_{2}, a_{3}, a_{4}$ are the coefficients of any four

consecutive terms in the expansion of ( $1 + x)^{n}$ , then

$\frac{a_{1}}{a_{1} + a_{2}}$ + $\frac{a_{3}}{a_{3} + a_{4}}$ =

The correct option is C

verify options