If a 1- a 2- a 3- a - n are in A- P- then the common difference is- A- a 2- a 1B- a 4- a 3C- a 7- a 6D- an-an-1

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Common Difference

If a 1, a 2, ...

Question

If $a_{1}, a_{2}, a_{3}$ .... a_{n} are in A. P., then the common difference is--

a_{2} - a_{1}

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a_{4} - a_{3}

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a_{n} - a_{n - 1}

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a_{7} - a_{6}

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a_{1}, a_{2}, a_{3}

a_{1}, a_{2}, a_{3}, . . . . . . . a_{n}

a_{1} = 0

d \neq 0

\frac{a_{3} - a_{2}}{a_{2}} + \frac{a_{4} - a_{2}}{a_{3}} + \frac{a_{5} - a_{2}}{a_{4}} . . . . . . . . . . . . \frac{a_{n} - a_{2}}{a_{n - 1}}

If $a_{1}, a_{2}, a_{3}, a_{4}$ are the coefficients of any four

consecutive terms in the expansion of ( $1 + x)^{n}$ , then

$\frac{a_{1}}{a_{1} + a_{2}}$ + $\frac{a_{3}}{a_{3} + a_{4}}$ =

a, a_{2}, a_{3}, . . . ., a_{n}

n

a = 0

d \neq 0

\frac{a_{3} - a_{2}}{a_{2}} + \frac{a_{4} - a_{2}}{a_{3}} + \frac{a_{5} - a_{2}}{a_{4}} . . . . + \frac{a_{n} - a_{2}}{a_{n - 1}}

\frac{a_{1}}{a_{2}} + \frac{a_{2}}{a_{3}} + \frac{a_{3}}{a_{4}} + . . . . . + \frac{a_{n - 1}}{a_{n}} + \frac{a_{n}}{a_{1}} > n

a_{1}, a_{2}, . . ., a_{n}

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