If a1-a2-a3-an are in H-P then a1a2-a3-an-a2a1-a3-an-a3a1-a2-a4-an- ana1-a2-an are in

The correct option is C H.PIf #160; a_1,a_2,a_3,...a_n #160; #160; are in H.P #160; then 1a_1,1/a_2,1a_3,...1a_n in A.PAlso, #160;a_1+a_ ...

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Harmonic Progression

If a1,a2,a3...

Question

If $a_{1}, a_{2}, a_{3}, . . . a_{n}$ are in H.P then
$\frac{a_{1}}{a_{2} + a_{3} + . . . a_{n}}, \frac{a_{2}}{a_{1} + a_{3} + . . . a_{n}}, \frac{a_{3}}{a_{1} + a_{2} + a_{4} + . . . + a_{n}}, \frac{a_{n}}{a_{1} + a_{2} + . . . + a_{n}}$ are in

A.P

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H.P

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A.G.P

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Similar questions

a_{1}, a_{2}, a_{3}, . . . . . a_{n}

\frac{a_{1}}{a_{2} + a_{3} + . . . a_{n}}, \frac{a_{2}}{a_{1} + a_{3} + . . . . + a_{n}}, \frac{a_{n}}{a_{1} + a_{2} + . . . + a_{n - 1}}

a_{1}, a_{2}, a_{3}, . . . . a_{n}

\frac{a_{1}}{a_{2} + a_{3} + . . . . + a_{n}}, \frac{a_{2}}{a_{1} + a_{3} + . . . . + a_{n}}, . . . ., \frac{a_{n}}{a_{1} + a_{2} + . . . . + a_{n - 1}}

a_{1}, a_{2}, a_{3}, . . . . . . a_{n}

a_{1} a_{2} + a_{2} a_{3} + a_{3} a_{4} . . . . + a_{n - 1} a_{n} =

a_{1}, a_{2}, a_{3}, . . . . ., a_{n}

\frac{a_{1}}{a_{2} + a_{3} + . . . a_{n}}, \frac{a_{2}}{a_{2} + a_{3} + . . . a_{n}}, \frac{a_{3}}{a_{2} + a_{3} + . . . a_{n}}

a_{1},

a_{2},

. . . . . a_{n}

H . P

a_{1} . a_{2} + a_{2} . a_{3} + a_{3} . a_{4} + . . . . . + a_{n - 1} . a_{n} =

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