If a1,a2,a3,⋯,ar are in G.P. with common ratio R, then the determinant ∣∣
∣∣ar+1ar+5ar+9ar+7ar+11ar+15ar+11ar+17ar+21∣∣
∣∣ is
A
Propotional to R
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B
Propotional to R2
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C
Independent of R
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D
Propotional to R3
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Solution
The correct option is C Independent of R We know that, ar+1=ARr
where, A= first term, R= common ratio ⇒Δ=∣∣
∣
∣∣ARrARr+4ARr+8ARr+6ARr+10ARr+14ARr+10ARr+16ARr+20∣∣
∣
∣∣
Taking ARr,ARr+6 and ARr+10 common from rows R1,R2 and R3 respectively, we get ⇒Δ=ARr⋅ARr+6⋅ARr+10∣∣
∣
∣∣1R4R81R4R81R6R10∣∣
∣
∣∣∴Δ=0
(∵ rows R1 and R2 are identical.)