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Question

If a1,a2,a3,,an is an arithmetic progression with common difference d, then evaluate the following expression
tan⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢tan1(d1+a1 a2)+tan1(d1+a2 a3)+tan1(d1+a3 a4)+tan1(d1+an1 an)+⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥

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Solution

Let
A=tan⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢ ⎢tan1(d1+a1 a2)+tan1(d1+a2 a3)+tan1(d1+a3 a4)+tan1(d1+an1 an)⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥ ⎥

a1,a2,a3,,an is an AP
d=a2a1=a3a2==anan1

A=tan⎢ ⎢ ⎢tan1a2a11+a1a2+tan1a3a21+a3a2++tan1anan11+an1an⎥ ⎥ ⎥

A=tan⎢ ⎢(tan1a2tan1a1)+(tan1a3tan1a2)++(tan1antan1an1)⎥ ⎥
[tan1xtan1y=tan1xy1+xy,xy>1]
A=tan(tan1antan1a1)
A=tan(tan1ana11+ana1)
A=ana11+ana1
[tan(tan1x)=x,x ϵ R]

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