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Question

If a1+a2,...,an are positive numbers such that a1a2...an=1, then their sum is :

A
A positive integer
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B
Divisible by n
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C
Never less than n
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D
None of these
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Solution

The correct option is A Never less than n
a1+a2+...ann>(a1a2a3....an)1n
a1+a2+....an>n1(a1a2...an=1)
The sum of a1s is never less than n.

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