If A1,A2 be two arithmetic means and G1,G2 be two geometric means between two positive numbers a and b, then A1+A2G1G2
A
aba+b
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B
2aba+b
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C
a+b2ab
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D
a+bab
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Solution
The correct option is Da+bab For convinience lets say a=p3,b=q3 Then G1=p2q G2=pq2 G1G2=p3∗q3=ab and b=a+3d d=(b−a)/3 A1=a+(b−a)/3=2a/3+b/3 A2=a+2d=a+(b−a)2/3=a/3+2b/3 A1+A2=a+b (A1+A2)/(G1G2)=(a+b)/ab