The correct option is D a2h1
a,a1,a2,b are in A.P.
Let common difference is d
Then d=b−a3
⇒a1=2a+b3 and a2=a+2b3
a,g1,g2,b are in G.P.
Let common ratio is r
Then r=(ba)1/3
⇒g1=a2/3b1/3 and g2=a1/3b2/3
a,h1,h2,b are in H.P.
⇒1a,1h1,1h2,1b are in A.P.
Let common difference is D
Then D=a−b3ab
⇒1h1=1a+(a−b3ab)=a+2b3abh1=3aba+2b
and 1h2=2a+b3ab
⇒h2=3ab2a+b
∴a1h2=ab=a2h1=g1g2